3(n+5)-1/2(n-2)=12

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Solution for 3(n+5)-1/2(n-2)=12 equation: 



3(n+5)-1/2(n-2)=12

We move all terms to the left:

3(n+5)-1/2(n-2)-(12)=0



Domain of the equation: 2(n-2)!=0

n∈R



We multiply parentheses

3n-1/2(n-2)+15-12=0

We multiply all the terms by the denominator


3n*2(n-2)+15*2(n-2)-12*2(n-2)-1=0

Wy multiply elements

6n^2(n+30n(n-24n(n-1=0

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