3(n+5)=31+5n

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Solution for 3(n+5)=31+5n equation: 



3(n+5)=31+5n

We move all terms to the left:

3(n+5)-(31+5n)=0

We add all the numbers together, and all the variables

3(n+5)-(5n+31)=0

We multiply parentheses

3n-(5n+31)+15=0

We get rid of parentheses

3n-5n-31+15=0

We add all the numbers together, and all the variables

-2n-16=0

We move all terms containing n to the left, all other terms to the right

-2n=16

n=16/-2

n=-8

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