3(n+5)=42-6n

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Solution for 3(n+5)=42-6n equation: 



3(n+5)=42-6n

We move all terms to the left:

3(n+5)-(42-6n)=0

We add all the numbers together, and all the variables

3(n+5)-(-6n+42)=0

We multiply parentheses

3n-(-6n+42)+15=0

We get rid of parentheses

3n+6n-42+15=0

We add all the numbers together, and all the variables

9n-27=0

We move all terms containing n to the left, all other terms to the right

9n=27

n=27/9

n=3

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