3(n-1)+4(n+1)=22

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Solution for 3(n-1)+4(n+1)=22 equation: 



3(n-1)+4(n+1)=22

We move all terms to the left:

3(n-1)+4(n+1)-(22)=0

We multiply parentheses

3n+4n-3+4-22=0

We add all the numbers together, and all the variables

7n-21=0

We move all terms containing n to the left, all other terms to the right

7n=21

n=21/7

n=3

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