3(n-1)+4(n+1)=22

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Solution for 3(n-1)+4(n+1)=22 equation:



3(n-1)+4(n+1)=22
We move all terms to the left:
3(n-1)+4(n+1)-(22)=0
We multiply parentheses
3n+4n-3+4-22=0
We add all the numbers together, and all the variables
7n-21=0
We move all terms containing n to the left, all other terms to the right
7n=21
n=21/7
n=3

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