3(n-1)+4=5(3n-2)+8

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Solution for 3(n-1)+4=5(3n-2)+8 equation: 



3(n-1)+4=5(3n-2)+8

We move all terms to the left:

3(n-1)+4-(5(3n-2)+8)=0

We multiply parentheses

3n-(5(3n-2)+8)-3+4=0



We calculate terms in parentheses: -(5(3n-2)+8), so:

5(3n-2)+8

We multiply parentheses

15n-10+8

We add all the numbers together, and all the variables

15n-2

Back to the equation:

-(15n-2)



We add all the numbers together, and all the variables

3n-(15n-2)+1=0

We get rid of parentheses

3n-15n+2+1=0

We add all the numbers together, and all the variables

-12n+3=0

We move all terms containing n to the left, all other terms to the right

-12n=-3

n=-3/-12

n=1/4

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