3(n-1)+4=5(3n-2)-2(3n-4)+3

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Solution for 3(n-1)+4=5(3n-2)-2(3n-4)+3 equation: 



3(n-1)+4=5(3n-2)-2(3n-4)+3

We move all terms to the left:

3(n-1)+4-(5(3n-2)-2(3n-4)+3)=0

We multiply parentheses

3n-(5(3n-2)-2(3n-4)+3)-3+4=0



We calculate terms in parentheses: -(5(3n-2)-2(3n-4)+3), so:

5(3n-2)-2(3n-4)+3

We multiply parentheses

15n-6n-10+8+3

We add all the numbers together, and all the variables

9n+1

Back to the equation:

-(9n+1)



We add all the numbers together, and all the variables

3n-(9n+1)+1=0

We get rid of parentheses

3n-9n-1+1=0

We add all the numbers together, and all the variables

-6n=0

n=0/-6

n=0

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