3(n-1)-2=(n-4)-(n-11)

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Solution for 3(n-1)-2=(n-4)-(n-11) equation: 


Simplifying
3(n + -1) + -2 = (n + -4) + -1(n + -11)

Reorder the terms:
3(-1 + n) + -2 = (n + -4) + -1(n + -11)
(-1 * 3 + n * 3) + -2 = (n + -4) + -1(n + -11)
(-3 + 3n) + -2 = (n + -4) + -1(n + -11)

Reorder the terms:
-3 + -2 + 3n = (n + -4) + -1(n + -11)

Combine like terms: -3 + -2 = -5
-5 + 3n = (n + -4) + -1(n + -11)

Reorder the terms:
-5 + 3n = (-4 + n) + -1(n + -11)

Remove parenthesis around (-4 + n)
-5 + 3n = -4 + n + -1(n + -11)

Reorder the terms:
-5 + 3n = -4 + n + -1(-11 + n)
-5 + 3n = -4 + n + (-11 * -1 + n * -1)
-5 + 3n = -4 + n + (11 + -1n)

Reorder the terms:
-5 + 3n = -4 + 11 + n + -1n

Combine like terms: -4 + 11 = 7
-5 + 3n = 7 + n + -1n

Combine like terms: n + -1n = 0
-5 + 3n = 7 + 0
-5 + 3n = 7

Solving
-5 + 3n = 7

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 3n = 7 + 5

Combine like terms: -5 + 5 = 0
0 + 3n = 7 + 5
3n = 7 + 5

Combine like terms: 7 + 5 = 12
3n = 12

Divide each side by '3'.
n = 4

Simplifying
n = 4

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