3(n-1)-2=4(n+2)+4

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Solution for 3(n-1)-2=4(n+2)+4 equation:


Simplifying
3(n + -1) + -2 = 4(n + 2) + 4

Reorder the terms:
3(-1 + n) + -2 = 4(n + 2) + 4
(-1 * 3 + n * 3) + -2 = 4(n + 2) + 4
(-3 + 3n) + -2 = 4(n + 2) + 4

Reorder the terms:
-3 + -2 + 3n = 4(n + 2) + 4

Combine like terms: -3 + -2 = -5
-5 + 3n = 4(n + 2) + 4

Reorder the terms:
-5 + 3n = 4(2 + n) + 4
-5 + 3n = (2 * 4 + n * 4) + 4
-5 + 3n = (8 + 4n) + 4

Reorder the terms:
-5 + 3n = 8 + 4 + 4n

Combine like terms: 8 + 4 = 12
-5 + 3n = 12 + 4n

Solving
-5 + 3n = 12 + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
-5 + 3n + -4n = 12 + 4n + -4n

Combine like terms: 3n + -4n = -1n
-5 + -1n = 12 + 4n + -4n

Combine like terms: 4n + -4n = 0
-5 + -1n = 12 + 0
-5 + -1n = 12

Add '5' to each side of the equation.
-5 + 5 + -1n = 12 + 5

Combine like terms: -5 + 5 = 0
0 + -1n = 12 + 5
-1n = 12 + 5

Combine like terms: 12 + 5 = 17
-1n = 17

Divide each side by '-1'.
n = -17

Simplifying
n = -17

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