3(n-1)-2=4(n-4)-n-11

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Solution for 3(n-1)-2=4(n-4)-n-11 equation:


Simplifying
3(n + -1) + -2 = 4(n + -4) + -1n + -11

Reorder the terms:
3(-1 + n) + -2 = 4(n + -4) + -1n + -11
(-1 * 3 + n * 3) + -2 = 4(n + -4) + -1n + -11
(-3 + 3n) + -2 = 4(n + -4) + -1n + -11

Reorder the terms:
-3 + -2 + 3n = 4(n + -4) + -1n + -11

Combine like terms: -3 + -2 = -5
-5 + 3n = 4(n + -4) + -1n + -11

Reorder the terms:
-5 + 3n = 4(-4 + n) + -1n + -11
-5 + 3n = (-4 * 4 + n * 4) + -1n + -11
-5 + 3n = (-16 + 4n) + -1n + -11

Reorder the terms:
-5 + 3n = -16 + -11 + 4n + -1n

Combine like terms: -16 + -11 = -27
-5 + 3n = -27 + 4n + -1n

Combine like terms: 4n + -1n = 3n
-5 + 3n = -27 + 3n

Add '-3n' to each side of the equation.
-5 + 3n + -3n = -27 + 3n + -3n

Combine like terms: 3n + -3n = 0
-5 + 0 = -27 + 3n + -3n
-5 = -27 + 3n + -3n

Combine like terms: 3n + -3n = 0
-5 = -27 + 0
-5 = -27

Solving
-5 = -27

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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