3(n-10)+2(n-29)=2

Solution for 3(n-10)+2(n-29)=2 equation:

Simplifying
3(n + -10) + 2(n + -29) = 2

Reorder the terms:
3(-10 + n) + 2(n + -29) = 2
(-10 * 3 + n * 3) + 2(n + -29) = 2
(-30 + 3n) + 2(n + -29) = 2

Reorder the terms:
-30 + 3n + 2(-29 + n) = 2
-30 + 3n + (-29 * 2 + n * 2) = 2
-30 + 3n + (-58 + 2n) = 2

Reorder the terms:
-30 + -58 + 3n + 2n = 2

Combine like terms: -30 + -58 = -88
-88 + 3n + 2n = 2

Combine like terms: 3n + 2n = 5n
-88 + 5n = 2

Solving
-88 + 5n = 2

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '88' to each side of the equation.
-88 + 88 + 5n = 2 + 88

Combine like terms: -88 + 88 = 0
0 + 5n = 2 + 88
5n = 2 + 88

Combine like terms: 2 + 88 = 90
5n = 90

Divide each side by '5'.
n = 18

Simplifying
n = 18