3(n-11)+10(7=3n)=2+2n+n+5

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Solution for 3(n-11)+10(7=3n)=2+2n+n+5 equation: 



3(n-11)+10(7=3n)=2+2n+n+5

We move all terms to the left:

3(n-11)+10(7-(3n))=0

We add all the numbers together, and all the variables

3(n-11)+10(-3n+7)=0

We multiply parentheses

3n-30n-33+70=0

We add all the numbers together, and all the variables

-27n+37=0

We move all terms containing n to the left, all other terms to the right

-27n=-37

n=-37/-27

n=1+10/27

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