3(n-2)+4(n+2)=

Solution for 3(n-2)+4(n+2)= equation:

Simplifying
3(n + -2) + 4(n + 2) = 0

Reorder the terms:
3(-2 + n) + 4(n + 2) = 0
(-2 * 3 + n * 3) + 4(n + 2) = 0
(-6 + 3n) + 4(n + 2) = 0

Reorder the terms:
-6 + 3n + 4(2 + n) = 0
-6 + 3n + (2 * 4 + n * 4) = 0
-6 + 3n + (8 + 4n) = 0

Reorder the terms:
-6 + 8 + 3n + 4n = 0

Combine like terms: -6 + 8 = 2
2 + 3n + 4n = 0

Combine like terms: 3n + 4n = 7n
2 + 7n = 0

Solving
2 + 7n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 7n = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 7n = 0 + -2
7n = 0 + -2

Combine like terms: 0 + -2 = -2
7n = -2

Divide each side by '7'.
n = -0.2857142857

Simplifying
n = -0.2857142857