3(n-2)+58=3(n-2)+58

Solution for 3(n-2)+58=3(n-2)+58 equation:

Simplifying
3(n + -2) + 58 = 3(n + -2) + 58

Reorder the terms:
3(-2 + n) + 58 = 3(n + -2) + 58
(-2 * 3 + n * 3) + 58 = 3(n + -2) + 58
(-6 + 3n) + 58 = 3(n + -2) + 58

Reorder the terms:
-6 + 58 + 3n = 3(n + -2) + 58

Combine like terms: -6 + 58 = 52
52 + 3n = 3(n + -2) + 58

Reorder the terms:
52 + 3n = 3(-2 + n) + 58
52 + 3n = (-2 * 3 + n * 3) + 58
52 + 3n = (-6 + 3n) + 58

Reorder the terms:
52 + 3n = -6 + 58 + 3n

Combine like terms: -6 + 58 = 52
52 + 3n = 52 + 3n

Add '-52' to each side of the equation.
52 + -52 + 3n = 52 + -52 + 3n

Combine like terms: 52 + -52 = 0
0 + 3n = 52 + -52 + 3n
3n = 52 + -52 + 3n

Combine like terms: 52 + -52 = 0
3n = 0 + 3n
3n = 3n

Add '-3n' to each side of the equation.
3n + -3n = 3n + -3n

Combine like terms: 3n + -3n = 0
0 = 3n + -3n

Combine like terms: 3n + -3n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.