3(n-2)+5=11-(7-n)

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Solution for 3(n-2)+5=11-(7-n) equation: 



3(n-2)+5=11-(7-n)

We move all terms to the left:

3(n-2)+5-(11-(7-n))=0

We add all the numbers together, and all the variables

3(n-2)-(11-(-1n+7))+5=0

We multiply parentheses

3n-(11-(-1n+7))-6+5=0



We calculate terms in parentheses: -(11-(-1n+7)), so:

11-(-1n+7)

determiningTheFunctionDomain
-(-1n+7)+11

We get rid of parentheses

1n-7+11

We add all the numbers together, and all the variables

n+4

Back to the equation:

-(n+4)



We add all the numbers together, and all the variables

3n-(n+4)-1=0

We get rid of parentheses

3n-n-4-1=0

We add all the numbers together, and all the variables

2n-5=0

We move all terms containing n to the left, all other terms to the right

2n=5

n=5/2

n=2+1/2

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