3(n-2)+7n=0.5(6n-2)

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Solution for 3(n-2)+7n=0.5(6n-2) equation: 



3(n-2)+7n=0.5(6n-2)

We move all terms to the left:

3(n-2)+7n-(0.5(6n-2))=0

We add all the numbers together, and all the variables

7n+3(n-2)-(0.5(6n-2))=0

We multiply parentheses

7n+3n-(0.5(6n-2))-6=0



We calculate terms in parentheses: -(0.5(6n-2)), so:

0.5(6n-2)

We multiply parentheses

3n-1

Back to the equation:

-(3n-1)



We add all the numbers together, and all the variables

10n-(3n-1)-6=0

We get rid of parentheses

10n-3n+1-6=0

We add all the numbers together, and all the variables

7n-5=0

We move all terms containing n to the left, all other terms to the right

7n=5

n=5/7

n=5/7

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