3(n-2)-19=5+2(n+5)

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Solution for 3(n-2)-19=5+2(n+5) equation:


Simplifying
3(n + -2) + -19 = 5 + 2(n + 5)

Reorder the terms:
3(-2 + n) + -19 = 5 + 2(n + 5)
(-2 * 3 + n * 3) + -19 = 5 + 2(n + 5)
(-6 + 3n) + -19 = 5 + 2(n + 5)

Reorder the terms:
-6 + -19 + 3n = 5 + 2(n + 5)

Combine like terms: -6 + -19 = -25
-25 + 3n = 5 + 2(n + 5)

Reorder the terms:
-25 + 3n = 5 + 2(5 + n)
-25 + 3n = 5 + (5 * 2 + n * 2)
-25 + 3n = 5 + (10 + 2n)

Combine like terms: 5 + 10 = 15
-25 + 3n = 15 + 2n

Solving
-25 + 3n = 15 + 2n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2n' to each side of the equation.
-25 + 3n + -2n = 15 + 2n + -2n

Combine like terms: 3n + -2n = 1n
-25 + 1n = 15 + 2n + -2n

Combine like terms: 2n + -2n = 0
-25 + 1n = 15 + 0
-25 + 1n = 15

Add '25' to each side of the equation.
-25 + 25 + 1n = 15 + 25

Combine like terms: -25 + 25 = 0
0 + 1n = 15 + 25
1n = 15 + 25

Combine like terms: 15 + 25 = 40
1n = 40

Divide each side by '1'.
n = 40

Simplifying
n = 40

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