3(n-2)-1=2+5(n+5)

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Solution for 3(n-2)-1=2+5(n+5) equation: 



3(n-2)-1=2+5(n+5)

We move all terms to the left:

3(n-2)-1-(2+5(n+5))=0

We multiply parentheses

3n-(2+5(n+5))-6-1=0



We calculate terms in parentheses: -(2+5(n+5)), so:

2+5(n+5)

determiningTheFunctionDomain
5(n+5)+2

We multiply parentheses

5n+25+2

We add all the numbers together, and all the variables

5n+27

Back to the equation:

-(5n+27)



We add all the numbers together, and all the variables

3n-(5n+27)-7=0

We get rid of parentheses

3n-5n-27-7=0

We add all the numbers together, and all the variables

-2n-34=0

We move all terms containing n to the left, all other terms to the right

-2n=34

n=34/-2

n=-17

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