3(n-2)-2(3-n)=4(n-3)

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Solution for 3(n-2)-2(3-n)=4(n-3) equation:


Simplifying
3(n + -2) + -2(3 + -1n) = 4(n + -3)

Reorder the terms:
3(-2 + n) + -2(3 + -1n) = 4(n + -3)
(-2 * 3 + n * 3) + -2(3 + -1n) = 4(n + -3)
(-6 + 3n) + -2(3 + -1n) = 4(n + -3)
-6 + 3n + (3 * -2 + -1n * -2) = 4(n + -3)
-6 + 3n + (-6 + 2n) = 4(n + -3)

Reorder the terms:
-6 + -6 + 3n + 2n = 4(n + -3)

Combine like terms: -6 + -6 = -12
-12 + 3n + 2n = 4(n + -3)

Combine like terms: 3n + 2n = 5n
-12 + 5n = 4(n + -3)

Reorder the terms:
-12 + 5n = 4(-3 + n)
-12 + 5n = (-3 * 4 + n * 4)
-12 + 5n = (-12 + 4n)

Add '12' to each side of the equation.
-12 + 12 + 5n = -12 + 12 + 4n

Combine like terms: -12 + 12 = 0
0 + 5n = -12 + 12 + 4n
5n = -12 + 12 + 4n

Combine like terms: -12 + 12 = 0
5n = 0 + 4n
5n = 4n

Solving
5n = 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
5n + -4n = 4n + -4n

Combine like terms: 5n + -4n = 1n
1n = 4n + -4n

Combine like terms: 4n + -4n = 0
1n = 0

Divide each side by '1'.
n = 0

Simplifying
n = 0

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