3(n-2)-2(n+2)=12

Solution for 3(n-2)-2(n+2)=12 equation:

Simplifying
3(n + -2) + -2(n + 2) = 12

Reorder the terms:
3(-2 + n) + -2(n + 2) = 12
(-2 * 3 + n * 3) + -2(n + 2) = 12
(-6 + 3n) + -2(n + 2) = 12

Reorder the terms:
-6 + 3n + -2(2 + n) = 12
-6 + 3n + (2 * -2 + n * -2) = 12
-6 + 3n + (-4 + -2n) = 12

Reorder the terms:
-6 + -4 + 3n + -2n = 12

Combine like terms: -6 + -4 = -10
-10 + 3n + -2n = 12

Combine like terms: 3n + -2n = 1n
-10 + 1n = 12

Solving
-10 + 1n = 12

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 1n = 12 + 10

Combine like terms: -10 + 10 = 0
0 + 1n = 12 + 10
1n = 12 + 10

Combine like terms: 12 + 10 = 22
1n = 22

Divide each side by '1'.
n = 22

Simplifying
n = 22