3(n-2)-4(n-1)=n+13

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Solution for 3(n-2)-4(n-1)=n+13 equation:


Simplifying
3(n + -2) + -4(n + -1) = n + 13

Reorder the terms:
3(-2 + n) + -4(n + -1) = n + 13
(-2 * 3 + n * 3) + -4(n + -1) = n + 13
(-6 + 3n) + -4(n + -1) = n + 13

Reorder the terms:
-6 + 3n + -4(-1 + n) = n + 13
-6 + 3n + (-1 * -4 + n * -4) = n + 13
-6 + 3n + (4 + -4n) = n + 13

Reorder the terms:
-6 + 4 + 3n + -4n = n + 13

Combine like terms: -6 + 4 = -2
-2 + 3n + -4n = n + 13

Combine like terms: 3n + -4n = -1n
-2 + -1n = n + 13

Reorder the terms:
-2 + -1n = 13 + n

Solving
-2 + -1n = 13 + n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-1n' to each side of the equation.
-2 + -1n + -1n = 13 + n + -1n

Combine like terms: -1n + -1n = -2n
-2 + -2n = 13 + n + -1n

Combine like terms: n + -1n = 0
-2 + -2n = 13 + 0
-2 + -2n = 13

Add '2' to each side of the equation.
-2 + 2 + -2n = 13 + 2

Combine like terms: -2 + 2 = 0
0 + -2n = 13 + 2
-2n = 13 + 2

Combine like terms: 13 + 2 = 15
-2n = 15

Divide each side by '-2'.
n = -7.5

Simplifying
n = -7.5

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