3(n-2)-4=2(n-1)-2

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Solution for 3(n-2)-4=2(n-1)-2 equation: 



3(n-2)-4=2(n-1)-2

We move all terms to the left:

3(n-2)-4-(2(n-1)-2)=0

We multiply parentheses

3n-(2(n-1)-2)-6-4=0



We calculate terms in parentheses: -(2(n-1)-2), so:

2(n-1)-2

We multiply parentheses

2n-2-2

We add all the numbers together, and all the variables

2n-4

Back to the equation:

-(2n-4)



We add all the numbers together, and all the variables

3n-(2n-4)-10=0

We get rid of parentheses

3n-2n+4-10=0

We add all the numbers together, and all the variables

n-6=0

We move all terms containing n to the left, all other terms to the right

n=6

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