3(n-2)-n=2(2n+1)

Solution for 3(n-2)-n=2(2n+1) equation:

3(n-2)-n=2(2n+1)

We move all terms to the left:

3(n-2)-n-(2(2n+1))=0

We add all the numbers together, and all the variables

-1n+3(n-2)-(2(2n+1))=0

We multiply parentheses

-1n+3n-(2(2n+1))-6=0


We calculate terms in parentheses: -(2(2n+1)), so:

2(2n+1)

We multiply parentheses

4n+2

Back to the equation:

-(4n+2)


We add all the numbers together, and all the variables

2n-(4n+2)-6=0

We get rid of parentheses

2n-4n-2-6=0

We add all the numbers together, and all the variables

-2n-8=0

We move all terms containing n to the left, all other terms to the right

-2n=8

n=8/-2

n=-4