3(n-2)2-13(n-2)+4=0

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Solution for 3(n-2)2-13(n-2)+4=0 equation:



3(n-2)2-13(n-2)+4=0
We multiply parentheses
6n-13n-12+26+4=0
We add all the numbers together, and all the variables
-7n+18=0
We move all terms containing n to the left, all other terms to the right
-7n=-18
n=-18/-7
n=2+4/7

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