3(n-2)=-4n+6(1-n)

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Solution for 3(n-2)=-4n+6(1-n) equation: 



3(n-2)=-4n+6(1-n)

We move all terms to the left:

3(n-2)-(-4n+6(1-n))=0

We add all the numbers together, and all the variables

3(n-2)-(-4n+6(-1n+1))=0

We multiply parentheses

3n-(-4n+6(-1n+1))-6=0



We calculate terms in parentheses: -(-4n+6(-1n+1)), so:

-4n+6(-1n+1)

We multiply parentheses

-4n-6n+6

We add all the numbers together, and all the variables

-10n+6

Back to the equation:

-(-10n+6)



We get rid of parentheses

3n+10n-6-6=0

We add all the numbers together, and all the variables

13n-12=0

We move all terms containing n to the left, all other terms to the right

13n=12

n=12/13

n=12/13

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