3(n-2)=-6+4n-n

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Solution for 3(n-2)=-6+4n-n equation: 



3(n-2)=-6+4n-n

We move all terms to the left:

3(n-2)-(-6+4n-n)=0

We add all the numbers together, and all the variables

3(n-2)-(3n-6)=0

We multiply parentheses

3n-(3n-6)-6=0

We get rid of parentheses

3n-3n+6-6=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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