3(n-2)=2(4-2n)

Solution for 3(n-2)=2(4-2n) equation:

3(n-2)=2(4-2n)

We move all terms to the left:

3(n-2)-(2(4-2n))=0

We add all the numbers together, and all the variables

3(n-2)-(2(-2n+4))=0

We multiply parentheses

3n-(2(-2n+4))-6=0


We calculate terms in parentheses: -(2(-2n+4)), so:

2(-2n+4)

We multiply parentheses

-4n+8

Back to the equation:

-(-4n+8)


We get rid of parentheses

3n+4n-8-6=0

We add all the numbers together, and all the variables

7n-14=0

We move all terms containing n to the left, all other terms to the right

7n=14

n=14/7

n=2