3(n-2)=4(n-5)

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Solution for 3(n-2)=4(n-5) equation:


Simplifying
3(n + -2) = 4(n + -5)

Reorder the terms:
3(-2 + n) = 4(n + -5)
(-2 * 3 + n * 3) = 4(n + -5)
(-6 + 3n) = 4(n + -5)

Reorder the terms:
-6 + 3n = 4(-5 + n)
-6 + 3n = (-5 * 4 + n * 4)
-6 + 3n = (-20 + 4n)

Solving
-6 + 3n = -20 + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
-6 + 3n + -4n = -20 + 4n + -4n

Combine like terms: 3n + -4n = -1n
-6 + -1n = -20 + 4n + -4n

Combine like terms: 4n + -4n = 0
-6 + -1n = -20 + 0
-6 + -1n = -20

Add '6' to each side of the equation.
-6 + 6 + -1n = -20 + 6

Combine like terms: -6 + 6 = 0
0 + -1n = -20 + 6
-1n = -20 + 6

Combine like terms: -20 + 6 = -14
-1n = -14

Divide each side by '-1'.
n = 14

Simplifying
n = 14

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