3(n-2)=9(6-n)

Solution for 3(n-2)=9(6-n) equation:

3(n-2)=9(6-n)

We move all terms to the left:

3(n-2)-(9(6-n))=0

We add all the numbers together, and all the variables

3(n-2)-(9(-1n+6))=0

We multiply parentheses

3n-(9(-1n+6))-6=0


We calculate terms in parentheses: -(9(-1n+6)), so:

9(-1n+6)

We multiply parentheses

-9n+54

Back to the equation:

-(-9n+54)


We get rid of parentheses

3n+9n-54-6=0

We add all the numbers together, and all the variables

12n-60=0

We move all terms containing n to the left, all other terms to the right

12n=60

n=60/12

n=5