3(n-3)+1=4n-2(n-1)

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Solution for 3(n-3)+1=4n-2(n-1) equation:


Simplifying
3(n + -3) + 1 = 4n + -2(n + -1)

Reorder the terms:
3(-3 + n) + 1 = 4n + -2(n + -1)
(-3 * 3 + n * 3) + 1 = 4n + -2(n + -1)
(-9 + 3n) + 1 = 4n + -2(n + -1)

Reorder the terms:
-9 + 1 + 3n = 4n + -2(n + -1)

Combine like terms: -9 + 1 = -8
-8 + 3n = 4n + -2(n + -1)

Reorder the terms:
-8 + 3n = 4n + -2(-1 + n)
-8 + 3n = 4n + (-1 * -2 + n * -2)
-8 + 3n = 4n + (2 + -2n)

Reorder the terms:
-8 + 3n = 2 + 4n + -2n

Combine like terms: 4n + -2n = 2n
-8 + 3n = 2 + 2n

Solving
-8 + 3n = 2 + 2n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2n' to each side of the equation.
-8 + 3n + -2n = 2 + 2n + -2n

Combine like terms: 3n + -2n = 1n
-8 + 1n = 2 + 2n + -2n

Combine like terms: 2n + -2n = 0
-8 + 1n = 2 + 0
-8 + 1n = 2

Add '8' to each side of the equation.
-8 + 8 + 1n = 2 + 8

Combine like terms: -8 + 8 = 0
0 + 1n = 2 + 8
1n = 2 + 8

Combine like terms: 2 + 8 = 10
1n = 10

Divide each side by '1'.
n = 10

Simplifying
n = 10

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