3(n-3)/4=2n-21

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Solution for 3(n-3)/4=2n-21 equation: 



3(n-3)/4=2n-21

We move all terms to the left:

3(n-3)/4-(2n-21)=0

We get rid of parentheses

3(n-3)/4-2n+21=0

We multiply all the terms by the denominator


3(n-3)-2n*4+21*4=0

We add all the numbers together, and all the variables

3(n-3)-2n*4+84=0

We multiply parentheses

3n-2n*4-9+84=0

Wy multiply elements

3n-8n-9+84=0

We add all the numbers together, and all the variables

-5n+75=0

We move all terms containing n to the left, all other terms to the right

-5n=-75

n=-75/-5

n=+15

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