3(n-3)=2(n+6)

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Solution for 3(n-3)=2(n+6) equation:



3(n-3)=2(n+6)
We move all terms to the left:
3(n-3)-(2(n+6))=0
We multiply parentheses
3n-(2(n+6))-9=0
We calculate terms in parentheses: -(2(n+6)), so:
2(n+6)
We multiply parentheses
2n+12
Back to the equation:
-(2n+12)
We get rid of parentheses
3n-2n-12-9=0
We add all the numbers together, and all the variables
n-21=0
We move all terms containing n to the left, all other terms to the right
n=21

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