3(n-3)=4n+1

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Solution for 3(n-3)=4n+1 equation:



3(n-3)=4n+1
We move all terms to the left:
3(n-3)-(4n+1)=0
We multiply parentheses
3n-(4n+1)-9=0
We get rid of parentheses
3n-4n-1-9=0
We add all the numbers together, and all the variables
-1n-10=0
We move all terms containing n to the left, all other terms to the right
-n=10
n=10/-1
n=-10

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