3(n-4)+2(4n-5)=5(n+2)+6

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Solution for 3(n-4)+2(4n-5)=5(n+2)+6 equation: 



3(n-4)+2(4n-5)=5(n+2)+6

We move all terms to the left:

3(n-4)+2(4n-5)-(5(n+2)+6)=0

We multiply parentheses

3n+8n-(5(n+2)+6)-12-10=0



We calculate terms in parentheses: -(5(n+2)+6), so:

5(n+2)+6

We multiply parentheses

5n+10+6

We add all the numbers together, and all the variables

5n+16

Back to the equation:

-(5n+16)



We add all the numbers together, and all the variables

11n-(5n+16)-22=0

We get rid of parentheses

11n-5n-16-22=0

We add all the numbers together, and all the variables

6n-38=0

We move all terms containing n to the left, all other terms to the right

6n=38

n=38/6

n=6+1/3

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