3(n-4)+2(4n-5)=5(n+2)+6

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Solution for 3(n-4)+2(4n-5)=5(n+2)+6 equation:



3(n-4)+2(4n-5)=5(n+2)+6
We move all terms to the left:
3(n-4)+2(4n-5)-(5(n+2)+6)=0
We multiply parentheses
3n+8n-(5(n+2)+6)-12-10=0
We calculate terms in parentheses: -(5(n+2)+6), so:
5(n+2)+6
We multiply parentheses
5n+10+6
We add all the numbers together, and all the variables
5n+16
Back to the equation:
-(5n+16)
We add all the numbers together, and all the variables
11n-(5n+16)-22=0
We get rid of parentheses
11n-5n-16-22=0
We add all the numbers together, and all the variables
6n-38=0
We move all terms containing n to the left, all other terms to the right
6n=38
n=38/6
n=6+1/3

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