3(n-4)+2=-22+5

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Solution for 3(n-4)+2=-22+5 equation: 



3(n-4)+2=-22+5

We move all terms to the left:

3(n-4)+2-(-22+5)=0

We add all the numbers together, and all the variables

3(n-4)+2-(-17)=0

We add all the numbers together, and all the variables

3(n-4)+19=0

We multiply parentheses

3n-12+19=0

We add all the numbers together, and all the variables

3n+7=0

We move all terms containing n to the left, all other terms to the right

3n=-7

n=-7/3

n=-2+1/3

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