3(n-4)+2n=8-(5-2n)

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Solution for 3(n-4)+2n=8-(5-2n) equation: 



3(n-4)+2n=8-(5-2n)

We move all terms to the left:

3(n-4)+2n-(8-(5-2n))=0

We add all the numbers together, and all the variables

3(n-4)+2n-(8-(-2n+5))=0

We add all the numbers together, and all the variables

2n+3(n-4)-(8-(-2n+5))=0

We multiply parentheses

2n+3n-(8-(-2n+5))-12=0



We calculate terms in parentheses: -(8-(-2n+5)), so:

8-(-2n+5)

determiningTheFunctionDomain
-(-2n+5)+8

We get rid of parentheses

2n-5+8

We add all the numbers together, and all the variables

2n+3

Back to the equation:

-(2n+3)



We add all the numbers together, and all the variables

5n-(2n+3)-12=0

We get rid of parentheses

5n-2n-3-12=0

We add all the numbers together, and all the variables

3n-15=0

We move all terms containing n to the left, all other terms to the right

3n=15

n=15/3

n=5

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