3(n-4)+n=24

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Solution for 3(n-4)+n=24 equation: 



3(n-4)+n=24

We move all terms to the left:

3(n-4)+n-(24)=0

We add all the numbers together, and all the variables

n+3(n-4)-24=0

We multiply parentheses

n+3n-12-24=0

We add all the numbers together, and all the variables

4n-36=0

We move all terms containing n to the left, all other terms to the right

4n=36

n=36/4

n=9

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