3(n-4)+n=4(n-3)

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Solution for 3(n-4)+n=4(n-3) equation:


Simplifying
3(n + -4) + n = 4(n + -3)

Reorder the terms:
3(-4 + n) + n = 4(n + -3)
(-4 * 3 + n * 3) + n = 4(n + -3)
(-12 + 3n) + n = 4(n + -3)

Combine like terms: 3n + n = 4n
-12 + 4n = 4(n + -3)

Reorder the terms:
-12 + 4n = 4(-3 + n)
-12 + 4n = (-3 * 4 + n * 4)
-12 + 4n = (-12 + 4n)

Add '12' to each side of the equation.
-12 + 12 + 4n = -12 + 12 + 4n

Combine like terms: -12 + 12 = 0
0 + 4n = -12 + 12 + 4n
4n = -12 + 12 + 4n

Combine like terms: -12 + 12 = 0
4n = 0 + 4n
4n = 4n

Add '-4n' to each side of the equation.
4n + -4n = 4n + -4n

Combine like terms: 4n + -4n = 0
0 = 4n + -4n

Combine like terms: 4n + -4n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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