3(n-4)-2(3n+4)=4(3-n)+5n+4

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Solution for 3(n-4)-2(3n+4)=4(3-n)+5n+4 equation:



3(n-4)-2(3n+4)=4(3-n)+5n+4
We move all terms to the left:
3(n-4)-2(3n+4)-(4(3-n)+5n+4)=0
We add all the numbers together, and all the variables
3(n-4)-2(3n+4)-(4(-1n+3)+5n+4)=0
We multiply parentheses
3n-6n-(4(-1n+3)+5n+4)-12-8=0
We calculate terms in parentheses: -(4(-1n+3)+5n+4), so:
4(-1n+3)+5n+4
We add all the numbers together, and all the variables
5n+4(-1n+3)+4
We multiply parentheses
5n-4n+12+4
We add all the numbers together, and all the variables
n+16
Back to the equation:
-(n+16)
We add all the numbers together, and all the variables
-3n-(n+16)-20=0
We get rid of parentheses
-3n-n-16-20=0
We add all the numbers together, and all the variables
-4n-36=0
We move all terms containing n to the left, all other terms to the right
-4n=36
n=36/-4
n=-9

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