3(n-4)-6=(6-n)(-3)

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Solution for 3(n-4)-6=(6-n)(-3) equation: 



3(n-4)-6=(6-n)(-3)

We move all terms to the left:

3(n-4)-6-((6-n)(-3))=0

We add all the numbers together, and all the variables

3(n-4)-((-1n+6)(-3))-6=0

We multiply parentheses

3n-((-1n+6)(-3))-12-6=0

We multiply parentheses ..

3n-((+3n-18))-12-6=0



We calculate terms in parentheses: -((+3n-18)), so:

(+3n-18)

We add all the numbers together, and all the variables

(3n-18)

We get rid of parentheses

3n-18

Back to the equation:

-(3n-18)



We add all the numbers together, and all the variables

3n-(3n-18)-18=0

We get rid of parentheses

3n-3n+18-18=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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