3(n-4)=-22-2n

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Solution for 3(n-4)=-22-2n equation: 



3(n-4)=-22-2n

We move all terms to the left:

3(n-4)-(-22-2n)=0

We add all the numbers together, and all the variables

3(n-4)-(-2n-22)=0

We multiply parentheses

3n-(-2n-22)-12=0

We get rid of parentheses

3n+2n+22-12=0

We add all the numbers together, and all the variables

5n+10=0

We move all terms containing n to the left, all other terms to the right

5n=-10

n=-10/5

n=-2

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