3(n-4)=2(n-1)

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Solution for 3(n-4)=2(n-1) equation:


Simplifying
3(n + -4) = 2(n + -1)

Reorder the terms:
3(-4 + n) = 2(n + -1)
(-4 * 3 + n * 3) = 2(n + -1)
(-12 + 3n) = 2(n + -1)

Reorder the terms:
-12 + 3n = 2(-1 + n)
-12 + 3n = (-1 * 2 + n * 2)
-12 + 3n = (-2 + 2n)

Solving
-12 + 3n = -2 + 2n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2n' to each side of the equation.
-12 + 3n + -2n = -2 + 2n + -2n

Combine like terms: 3n + -2n = 1n
-12 + 1n = -2 + 2n + -2n

Combine like terms: 2n + -2n = 0
-12 + 1n = -2 + 0
-12 + 1n = -2

Add '12' to each side of the equation.
-12 + 12 + 1n = -2 + 12

Combine like terms: -12 + 12 = 0
0 + 1n = -2 + 12
1n = -2 + 12

Combine like terms: -2 + 12 = 10
1n = 10

Divide each side by '1'.
n = 10

Simplifying
n = 10

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