3(n-4)=3(n+4)

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Solution for 3(n-4)=3(n+4) equation: 



3(n-4)=3(n+4)

We move all terms to the left:

3(n-4)-(3(n+4))=0

We multiply parentheses

3n-(3(n+4))-12=0



We calculate terms in parentheses: -(3(n+4)), so:

3(n+4)

We multiply parentheses

3n+12

Back to the equation:

-(3n+12)



We get rid of parentheses

3n-3n-12-12=0

We add all the numbers together, and all the variables

-24!=0

There is no solution for this equation

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