3(n-4)=4+n

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Solution for 3(n-4)=4+n equation: 



3(n-4)=4+n

We move all terms to the left:

3(n-4)-(4+n)=0

We add all the numbers together, and all the variables

3(n-4)-(n+4)=0

We multiply parentheses

3n-(n+4)-12=0

We get rid of parentheses

3n-n-4-12=0

We add all the numbers together, and all the variables

2n-16=0

We move all terms containing n to the left, all other terms to the right

2n=16

n=16/2

n=8

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