3(n-5)+4=64

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Solution for 3(n-5)+4=64 equation: 



3(n-5)+4=64

We move all terms to the left:

3(n-5)+4-(64)=0

We add all the numbers together, and all the variables

3(n-5)-60=0

We multiply parentheses

3n-15-60=0

We add all the numbers together, and all the variables

3n-75=0

We move all terms containing n to the left, all other terms to the right

3n=75

n=75/3

n=25

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