3(n-5)-(2n+2)=2(n-1)

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Solution for 3(n-5)-(2n+2)=2(n-1) equation:


Simplifying
3(n + -5) + -1(2n + 2) = 2(n + -1)

Reorder the terms:
3(-5 + n) + -1(2n + 2) = 2(n + -1)
(-5 * 3 + n * 3) + -1(2n + 2) = 2(n + -1)
(-15 + 3n) + -1(2n + 2) = 2(n + -1)

Reorder the terms:
-15 + 3n + -1(2 + 2n) = 2(n + -1)
-15 + 3n + (2 * -1 + 2n * -1) = 2(n + -1)
-15 + 3n + (-2 + -2n) = 2(n + -1)

Reorder the terms:
-15 + -2 + 3n + -2n = 2(n + -1)

Combine like terms: -15 + -2 = -17
-17 + 3n + -2n = 2(n + -1)

Combine like terms: 3n + -2n = 1n
-17 + 1n = 2(n + -1)

Reorder the terms:
-17 + 1n = 2(-1 + n)
-17 + 1n = (-1 * 2 + n * 2)
-17 + 1n = (-2 + 2n)

Solving
-17 + 1n = -2 + 2n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2n' to each side of the equation.
-17 + 1n + -2n = -2 + 2n + -2n

Combine like terms: 1n + -2n = -1n
-17 + -1n = -2 + 2n + -2n

Combine like terms: 2n + -2n = 0
-17 + -1n = -2 + 0
-17 + -1n = -2

Add '17' to each side of the equation.
-17 + 17 + -1n = -2 + 17

Combine like terms: -17 + 17 = 0
0 + -1n = -2 + 17
-1n = -2 + 17

Combine like terms: -2 + 17 = 15
-1n = 15

Divide each side by '-1'.
n = -15

Simplifying
n = -15

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