3(n-5)-4(1-n)=2(5n+4)

Solution for 3(n-5)-4(1-n)=2(5n+4) equation:

3(n-5)-4(1-n)=2(5n+4)

We move all terms to the left:

3(n-5)-4(1-n)-(2(5n+4))=0

We add all the numbers together, and all the variables

3(n-5)-4(-1n+1)-(2(5n+4))=0

We multiply parentheses

3n+4n-(2(5n+4))-15-4=0


We calculate terms in parentheses: -(2(5n+4)), so:

2(5n+4)

We multiply parentheses

10n+8

Back to the equation:

-(10n+8)


We add all the numbers together, and all the variables

7n-(10n+8)-19=0

We get rid of parentheses

7n-10n-8-19=0

We add all the numbers together, and all the variables

-3n-27=0

We move all terms containing n to the left, all other terms to the right

-3n=27

n=27/-3

n=-9