3(n-5)/2=2(n+5)/3

Solution for 3(n-5)/2=2(n+5)/3 equation:

3(n-5)/2=2(n+5)/3

We move all terms to the left:

3(n-5)/2-(2(n+5)/3)=0

We calculate fractions


3n/()+(-(2(n+5)*2)/()=0


We calculate terms in parentheses: +(-(2(n+5)*2)/(), so:

-(2(n+5)*2)/(

We multiply all the terms by the denominator


-(2(n+5)*2)


We calculate terms in parentheses: -(2(n+5)*2), so:

2(n+5)*2

We multiply parentheses

4n+20

Back to the equation:

-(4n+20)


We get rid of parentheses

-4n-20

Back to the equation:

+(-4n-20)


We get rid of parentheses

3n/()-4n-20=0

We multiply all the terms by the denominator


3n-4n*()-20*()=0

We add all the numbers together, and all the variables

3n-4n*()=0