3(n-5)2-4=11(n-5)

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Solution for 3(n-5)2-4=11(n-5) equation: 



3(n-5)2-4=11(n-5)

We move all terms to the left:

3(n-5)2-4-(11(n-5))=0

We multiply parentheses

6n-(11(n-5))-30-4=0



We calculate terms in parentheses: -(11(n-5)), so:

11(n-5)

We multiply parentheses

11n-55

Back to the equation:

-(11n-55)



We add all the numbers together, and all the variables

6n-(11n-55)-34=0

We get rid of parentheses

6n-11n+55-34=0

We add all the numbers together, and all the variables

-5n+21=0

We move all terms containing n to the left, all other terms to the right

-5n=-21

n=-21/-5

n=4+1/5

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