3(n-5)=2(n-4)

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Solution for 3(n-5)=2(n-4) equation: 



3(n-5)=2(n-4)

We move all terms to the left:

3(n-5)-(2(n-4))=0

We multiply parentheses

3n-(2(n-4))-15=0



We calculate terms in parentheses: -(2(n-4)), so:

2(n-4)

We multiply parentheses

2n-8

Back to the equation:

-(2n-8)



We get rid of parentheses

3n-2n+8-15=0

We add all the numbers together, and all the variables

n-7=0

We move all terms containing n to the left, all other terms to the right

n=7

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