3(n-5)=21*

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Solution for 3(n-5)=21* equation: 



3(n-5)=21*

We move all terms to the left:

3(n-5)-(21*)=0

We add all the numbers together, and all the variables

3(n-5)-0=0

We add all the numbers together, and all the variables

3(n-5)=0

We multiply parentheses

3n-15=0

We move all terms containing n to the left, all other terms to the right

3n=15

n=15/3

n=5

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